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so the conclusion is : the function been call's  input parameter is  pointer address.

#include  <stdio.h>

 

 void fun0 (char a[])

{

char c = a[1];//或者是 char c = *(p+3);

printf("c is : %c\n",c);

}

void fun1 (char *p)

{

char v = p[1];//或者是 char c = *(p+3);

printf("v is : %c",v);

}

int main ()

{

char *p2 = "abcdefg";

fun0(p2);

fun1(p2);

return 0;

}

//end is same  (c)

//so the conclusion is : the function been call's  input parameter is  pointer address.(函数传参传入的是指针地址，不传数组)

 

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